WebSolution 1. Draw on such that is parallel to . Triangles and are similar, and since , they are also congruent, and so and . implies , so , . Since , , and since , all of these are equal to , and so the altitude of triangle is equal to of the altitude of . The area of is , so the area of . WebApr 14, 2024 · Normally the ST-segment gradually merges with the T wave (Fig. 20.2, marked *). If the ST-segment rises from the j point, it is known as early uptake of the ST-segment (Fig. 20.2 marked as ↓). This is usually the earliest change in the ST-segment during acute myocardial infarction .
In the following figure, O is the centre of a circular arc ... - Brainly
WebJul 8, 2024 · Answer: Answer Given angle of arc = 120 degrees radius of circle = 21 cm Area of circle = π*r^2 =3.14*21*21 =1386 cm2 Area of Arc= (angle of arc/ 360)*area of circle = … Webmade of objects, such as the length of a segment, the size of an angle, the area of a polygon, the circumference of a circle, or the coordinates of a point. ... Area ABC = 2.45 cm2 Fig. 2.1 Fig. 2.2 ota779g morris oxford
Anatomical variability of kidney arterial vasculature based on …
Web1) In the diagram, if the area of the segment ACB is 88.35 sq ft and the area of sector OACB is 130.12 sq ft, what is the area of the isosceles triangle AOB? 2)Segment ACB is shown … WebWe use the formula for area of sector of the circle to solve the problem. Since quadrant means 1/4 th of a complete circle, therefore, the angle at the centre of a quadrant of a … WebJan 23, 2024 · In an equilateral triangle ABC, D is a point on side BC such that BD = 1/3 BC then AB2 = Q8. In ABC, ∠B = 90°, AB = 12 cm and AC = 15 cm. D and E are points on AB and AC respectively such that ∠AED = 90° and DE = 3 cm then the area of ADE is Q9. If an angle is equal to one-fifth its compliment, then the angle is: ota and ima